Additional Mathematics
06062025–2027 syllabus

ADDITIONAL MATHEMATICS · CHAPTER 3

Factors of polynomials

Use substitution and division to turn a high-degree expression into solvable factors.

Additional Mathematics4 connected sectionsSyllabus-aligned guide

LEARNING OBJECTIVES

What you will be able to do

  • apply the remainder theorem
  • use the factor theorem in both directions
  • divide a polynomial by a linear expression
  • factorise and solve cubic equations

AT A GLANCE

Syllabus0606Coverage2025–2027Sections4LevelAdditional Mathematics

INTRODUCTION · THE BIG IDEA

Use substitution and division to turn a high-degree expression into solvable factors.

Polynomial questions often hide one accessible linear factor. A quick substitution can test a proposed factor or turn information about a remainder into an equation for an unknown coefficient.

Once a cubic is divided by one linear factor, the remaining quadratic can be handled with familiar methods.

01

SECTION 01

Remainder and factor theorems

Core concept

Dividing f(x) by x − a leaves remainder f(a). For a divisor such as 2x + 3, use its zero x = −3/2 in the same way.

RULE 1
remainder on division by (x − a) = f(a)
RULE 2
(x − a) is a factor ⇔ f(a) = 0
Original worked example

Determine an unknown coefficient

  1. Let f(x) = x³ + kx² − 5x + 6 and suppose x − 2 is a factor.
  2. Use f(2) = 0.
  3. Compute 8 + 4k − 10 + 6 = 0.
  4. Solve 4k + 4 = 0.

Answer: k = −1.

02

SECTION 02

Polynomial division

Core concept

Long division matches leading terms, multiplies back and subtracts repeatedly. Include zero placeholders for missing powers so columns remain aligned.

DETAILED EXPLANATION

  • The quotient degree is the dividend degree minus divisor degree.
  • The identity dividend = divisor × quotient + remainder can check the result.
ORIGINAL STUDY DIAGRAMDivide without losing a term
1Order descending powers
2Insert zero coefficients
3Divide leading terms
4Multiply and subtract
5Repeat to the remainder
03

SECTION 03

Factorising cubic polynomials

Core concept

Test likely rational roots, obtain a linear factor, then divide to get a quadratic. Factorise the quadratic if possible; otherwise use the quadratic formula.

RULE 1
f(x) = (x − a)(quadratic) when f(a) = 0
Useful root clues
Given informationImmediate test
x − a is a factorsubstitute x = a
x + a is a factorsubstitute x = −a
integer constant termtest integer divisors of the constant
remainder r on division by x − aset f(a) = r
04

SECTION 04

Cubic equations and graph links

Core concept

A fully factorised cubic equals zero when any factor equals zero. Repeated factors create repeated roots, while the sign of the leading coefficient controls end behaviour.

DETAILED EXPLANATION

  • List all real solutions after setting each factor to zero.
  • A cubic with three distinct linear factors crosses the axis at each simple root.
  • A repeated even-multiplicity factor touches rather than crosses.
  • Substitute roots back if coefficients or divisions were complicated.

QUICK CHAPTER SUMMARY

The ideas to carry forward

  • The remainder from division by x − a is f(a).
  • A zero remainder establishes a factor.
  • Polynomial division reduces the degree systematically.
  • One cubic root leads to a quadratic factor.
  • A cubic equation is solved only after every factor has been considered.

QUICK REVISION CHECKLIST

Can you do each of these without your notes?

  • apply the remainder theorem
  • use the factor theorem in both directions
  • divide a polynomial by a linear expression
  • factorise and solve cubic equations