Physics
06252026–2028 syllabus

PHYSICS · CHAPTER 5

Electricity

Connect charge, current, potential difference, resistance and energy in safe circuits.

Core + Supplement4 connected sectionsSyllabus-aligned guide

LEARNING OBJECTIVES

What you will be able to do

  • explain electrostatic charging and electric fields
  • apply charge, current, voltage, resistance and power equations
  • analyse series and parallel circuits
  • describe component behaviour, mains safety and electrical energy use

AT A GLANCE

Syllabus0625Coverage2026–2028Sections4LevelCore + Supplement

INTRODUCTION · THE BIG IDEA

Connect charge, current, potential difference, resistance and energy in safe circuits.

Electric circuits transfer energy through moving charge. Current describes charge flow, potential difference describes energy transferred per charge, and resistance describes opposition to current.

Circuit rules follow from conservation of charge and energy. They also explain why homes use parallel circuits and why fuses, circuit breakers and earthing reduce danger.

01

SECTION 01

Charge, current and electric fields

Core concept

Friction can transfer electrons between insulating materials. Gaining electrons makes an object negative; losing them makes it positive. Like charges repel and unlike charges attract.

An electric field is a region where a charge experiences a force. Field lines point from positive to negative and closer spacing represents a stronger field. Conventional current is defined from positive to negative, opposite electron flow in metals.

RULE 1
charge = current × time (Q = It)
Original worked example

Charge through a lamp

  1. A current of 0.35 A flows for 4.0 min.
  2. Convert time: 4.0 min = 240 s.
  3. Q = 0.35 × 240.

Answer: 84 C of charge passes.

02

SECTION 02

Potential difference, resistance and components

Core concept

Potential difference is energy transferred per unit charge; electromotive force is energy supplied per unit charge by a source. Resistance depends on material, length, cross-sectional area and temperature.

An ohmic conductor at constant temperature has current proportional to voltage. A filament lamp's resistance rises as it heats. An LDR has lower resistance in brighter light; a thermistor used here has lower resistance at higher temperature.

RULE 1
potential difference = energy transferred ÷ charge (V = E/Q)
RULE 2
resistance = potential difference ÷ current (R = V/I)
Component responses
ComponentInput changeResistance response
Filament lamptemperature risesincreases
LDRlight intensity risesdecreases
NTC thermistortemperature risesdecreases
03

SECTION 03

Series and parallel circuits

Core concept

In series, current is the same throughout, supply voltage is shared and resistances add. In parallel, voltage is the same across each branch and branch currents add to the supply current.

Adding a parallel branch lowers total resistance and increases total supply current. Potential dividers use series components to produce a variable output voltage, often with a sensor.

RULE 1
series resistance: Rₜ = R₁ + R₂ + …
RULE 2
parallel current: Iₜ = I₁ + I₂ + …
RULE 3
two parallel resistors: 1/Rₜ = 1/R₁ + 1/R₂
Original worked example

Two resistors in parallel

  1. 6 Ω and 3 Ω resistors are connected in parallel.
  2. 1/R = 1/6 + 1/3 = 3/6.
  3. R = 2 Ω.

Answer: Combined resistance = 2 Ω, less than either branch resistance.

04

SECTION 04

Electrical power, energy and safety

Core concept

Electrical power is the rate of energy transfer. Kilowatt-hour is a unit of energy used for billing: one kilowatt-hour is the energy transferred by 1 kW in 1 hour.

A fuse melts or a circuit breaker opens when current is excessive. The live wire is dangerous because it is at high potential; the neutral completes the circuit; the earth wire keeps a metal case near zero potential. Double-insulated appliances do not require an earth wire.

RULE 1
power = IV
RULE 2
power = I²R
RULE 3
power = V²/R
RULE 4
electrical energy = IVt
RULE 5
energy in kWh = power in kW × time in h
RULE 6
cost = energy in kWh × price per kWh
Original worked example

Cost of using a heater

  1. A 2.0 kW heater runs for 3.5 h.
  2. Energy = 2.0 × 3.5 = 7.0 kWh.
  3. At $0.24 per kWh, cost = 7.0 × 0.24.

Answer: The cost is $1.68.

QUICK CHAPTER SUMMARY

The ideas to carry forward

  • Current is charge flow; voltage is energy per charge.
  • Series and parallel circuits obey different conservation rules.
  • Component resistance can change with temperature or light.
  • Safety devices interrupt dangerous currents or provide a low-resistance path to earth.

QUICK REVISION CHECKLIST

Can you do each of these without your notes?

  • explain electrostatic charging and electric fields
  • apply charge, current, voltage, resistance and power equations
  • analyse series and parallel circuits
  • describe component behaviour, mains safety and electrical energy use